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Given-f-x-k-0-n-n-C-k-sin-kx-cos-n-k-x-Find-a-simple-form-for-f-x-Your-answer-should-be-written-like-c-n-g-nx-




Question Number 50908 by Smail last updated on 22/Dec/18
Given f(x)=Σ_(k=0) ^n ^n C_k sin(kx)cos((n−k)x)  Find a simple form for f(x)  (Your answer should be written like c(n).g(nx))
Givenf(x)=nk=0nCksin(kx)cos((nk)x)Findasimpleformforf(x)(Youranswershouldbewrittenlikec(n).g(nx))
Answered by Smail last updated on 23/Dec/18
f(x)=Σ_(k=0) ^n ^n C_k sin(kx)cos((n−k)x)  let l=n−k  f(x)=Σ_(l=0) ^n ^n C_(n−l) sin((n−l)x)cos(lx)  =Σ_(l=0) ^n ^n C_l sin((n−l)x)cos(lx)  2f(x)=Σ_(k=0) ^n ^n C_k (sin((n−k)x)cos(kx)+sin(kx)cos((n−k)x))  =Σ_(k=0) ^n ^n C_k (sin((n−k)x+kx))  2f(x)=Σ_(k=0) ^n ^n C_k sin(nx)=2^n sin(nx)  f(x)=2^(n−1) sin(nx)
f(x)=nk=0nCksin(kx)cos((nk)x)letl=nkf(x)=nl=0nCnlsin((nl)x)cos(lx)=nl=0nClsin((nl)x)cos(lx)2f(x)=nk=0nCk(sin((nk)x)cos(kx)+sin(kx)cos((nk)x))=nk=0nCk(sin((nk)x+kx))2f(x)=nk=0nCksin(nx)=2nsin(nx)f(x)=2n1sin(nx)

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