given-lim-x-2x-p-2x-1-2x-p-1-4-p-find-p-

Question Number 80828 by jagoll last updated on 07/Feb/20

g i v e n

\lim_{x \to - \infty} [\sqrt{2 x + p} - \sqrt{2 x + 1}] \times \sqrt{2 x - p} = \frac{1}{4} p

f i n d p .

Commented by john santu last updated on 07/Feb/20

\lim_{x \to - \infty} \sqrt{4 x^{2} - p^{2}} - \sqrt{4 x^{2} + (2 - 2 p) x - p} = \frac{1}{4} p

s i m i l a r t o

\lim_{x \to + \infty} \sqrt{4 x^{2} - p^{2}} - \sqrt{4 x^{2} + (2 p - 2) x - p} = \frac{1}{4} p

\frac{0 - (2 p - 2}{2.2} = \frac{p}{4} \Rightarrow p = \frac{2}{3}

Commented by jagoll last updated on 07/Feb/20

t h x

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