Given-t-x-ax-4-bx-2-x-5-where-a-and-b-are-constant-If-t-4-3-then-t-4-

Question Number 128176 by liberty last updated on 05/Jan/21

Given t (x) = {ax}^{4} + {bx}^{2} + x + 5; where a and b

are constant . If t (- 4) = 3 then t (4) = ?

Answered by bemath last updated on 05/Jan/21

(\Rightarrow) t (x) = {ax}^{4} + {bx}^{2} + x + 5

(\Rightarrow) t (4) = 256 a + 16 b + 9

we have t (- 4) = 256 a + 16 b + 1

so t (- 4) gives us 256 a + 16 b = 2

so we find t (4) = 256 a + 16 b + 9 = 2 + 9 = 11

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