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Question Number 119391 by Don08q last updated on 24/Oct/20

Given that f (x - 3) = x^{2} - 12 x + 41

find an explicit expression for f (x)

p l e a s e I n e e d t h e p r o c e d u r e

Answered by bemath last updated on 24/Oct/20

l e t x - 3 = t, x = t + 3

f (t) = {(t + 3)}^{2} - 12 (t + 3) + 41

f (t) = t^{2} + 6 t + 9 - 12 t - 36 + 41

f (t) = t^{2} - 6 t + 14, r e p l a c e t b y x

f (x) = x^{2} - 6 x + 14

Commented by Don08q last updated on 24/Oct/20

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