Given-that-f-x-determinant-x-x-2-x-3-1-2x-3x-2-0-2-6x-find-f-x-

Question Number 64350 by Rio Michael last updated on 16/Jul/19

G i v e n t h a t f (x) = | \begin{matrix} x & x^{2} & x^{3} \\ 1 & 2 x & 3 x^{2} \\ 0 & 2 & 6 x \end{matrix} |, f i n d f^{'} (x)

Commented by Tony Lin last updated on 17/Jul/19

f (x) = 12 x^{3} + 2 x^{3} - 6 x^{3} - 6 x^{3} = 2 x^{3}

f^{'} (x) = 6 x^{2}

Commented by Rio Michael last updated on 17/Jul/19

t h a n k s

Commented by Prithwish sen last updated on 17/Jul/19

f^{'} (x) = | \begin{matrix} 1 2 x {3 x}^{2} \\ 0 2 6 x \end{matrix} | = {12 x}^{2} - {6 x}^{2} = {6 x}^{2}

0 0 6