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Given-that-log-3x-1-2x-1-log-3x-1-5-find-the-value-of-x-




Question Number 54875 by shaddie last updated on 13/Feb/19
Given that((log(3x+1)^(2x−1) )/(log(3x+1)))=5,find the value of x.
Giventhatlog(3x+1)2x1log(3x+1)=5,findthevalueofx.
Answered by kaivan.ahmadi last updated on 14/Feb/19
log(3x+1)^(2x−1) =log(3x+1)^5 ⇒  (3x+1)^(2x−1) =(3x+1)^5 ⇒2x−1=5⇒  x=3
log(3x+1)2x1=log(3x+1)5(3x+1)2x1=(3x+1)52x1=5x=3
Answered by Otchere Abdullai last updated on 14/Feb/19
solution  ((log(3x+1)^(2x−1) )/(log(3x+1)))=5  ⇒(((2x−1)log(3x+1))/(log(3x+1)))=5  ⇒2x−1=5  ⇒2x=5+1  ⇒2x=6  ⇒((2x)/2)=(6/2)  ⇒x=3
solutionlog(3x+1)2x1log(3x+1)=5(2x1)log(3x+1)log(3x+1)=52x1=52x=5+12x=62x2=62x=3

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