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given-that-log2-0-3010-log3-0-477-log5-0-699-find-the-values-of-log-0-2-




Question Number 52030 by Water last updated on 02/Jan/19
given that log2=0.3010 log3=0.477 log5=0.699  find the values of log(√((0.2)))
giventhatlog2=0.3010log3=0.477log5=0.699findthevaluesoflog(0.2)
Answered by afachri last updated on 02/Jan/19
log ((2/(10)))^(0.5) = 0.5 log ((2/(10)))                            = 0.5 (log 2 − log 10)                            = 0.5 (0.3010 − 1)                             = − 0.3495
log(210)0.5=0.5log(210)=0.5(log2log10)=0.5(0.30101)=0.3495

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