Given-that-sin-A-1-2-and-sin-C-3-2-without-u-using-calculator-solve-a-tan-A-C-b-cos-A-C-

Question Number 89662 by 974342176 last updated on 18/Apr/20

G i v e n t h a t \sin A = \frac{1}{2} a n d \sin C = \frac{\sqrt{3}}{2} w i t h o u t u

u s i n g c a l c u l a t o r s o l v e

a) \tan (A + C)

b) c o s (A - C)

Answered by TANMAY PANACEA. last updated on 18/Apr/20

s i n A = \frac{1}{2} = s i n 30^{o} \to A = 30^{o}

s i n C = \frac{\sqrt{3}}{2} = s i n 60^{o} \to C = 60^{o}

t a n (A + C) = t a n (90^{o}) = \infty

c o s (A - C) = c o s (- 30^{o}) = c o s (30^{o}) = \frac{\sqrt{3}}{2}

Commented by jagoll last updated on 19/Apr/20

how about C = 120^{o}

then \tan (A + C) = \tan 150^{o}

= - \tan 30^{o} = - \frac{1}{\sqrt{3}}

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