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Given-that-x-2-y-2-73-and-xy-12-find-the-value-of-x-y-2-




Question Number 150299 by otchereabdullai@gmail.com last updated on 10/Aug/21
Given that x^2 +y^2 =73 and xy=12 ,   find the value of (x+y)^2
Giventhatx2+y2=73andxy=12,findthevalueof(x+y)2
Answered by cherokeesay last updated on 10/Aug/21
x^2 +y^2 +2xy=(x+y)^2 =73+24=97
x2+y2+2xy=(x+y)2=73+24=97
Commented by otchereabdullai@gmail.com last updated on 10/Aug/21
Thank you sir!
Thankyousir!
Answered by puissant last updated on 11/Aug/21
(x+y)^2 =x^2 +y^2 +2xy  ⇒ (x+y)^2 =73+24=97..
(x+y)2=x2+y2+2xy(x+y)2=73+24=97..

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