Given-the-curve-y-x-4-3x-3-6x-2-3x-determine-for-which-value-of-the-tangent-to-the-curve-from-point-P-0-is-maximum-

Question Number 159874 by tounghoungko last updated on 22/Nov/21

G i v e n t h e c u r v e y = x^{4} + 3 x^{3} - 6 x^{2} - 3 x

d e t e r m i n e f o r w h i c h v a l u e

o f α t h e t a n g e n t t o t h e c u r v e

f r o m p o i n t P (α, 0) i s m a x i m u m .

Commented by mr W last updated on 22/Nov/21

w h a t d o y o u m e a n w i t h “ t h e t a n g e n t

t o t h e c u r v e i s {m a x i m u m}^{″} ?

Commented by tounghoungko last updated on 22/Nov/21

t h e t a n g e n t w i t h s l o p e m a x i m u m

Commented by mr W last updated on 22/Nov/21

n o s o l u t i o n!

s i n c e w h e n x \to + \infty, y^{'} \to + \infty

Facebook Tweet Pin