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given-these-bellow-sequenses-find-fifth-term-1-1-5-1-4-3-11-2-7-2-3-5-9-11-25-19-57-35-3-1-6-7-11-13-16-19-21-4




Question Number 91785 by zainal tanjung last updated on 03/May/20
given  these bellow sequenses .   find fifth term    1).  (1/5), (1/4) , (3/(11)), (2/7),...  2).  (3/5), ((−9)/(11)) , ((−25)/(19)), ((57)/(35)),...  3).   (1/6), (7/(11)) , ((13)/(16)), ((19)/(21)),...  4).   4,− (2/3) , −(4/(13)),− (1/5),...  5).  2, 9 , 28 , 65,...
$$\mathrm{given}\:\:\mathrm{these}\:\mathrm{bellow}\:\mathrm{sequenses}\:.\: \\ $$$$\mathrm{find}\:\mathrm{fifth}\:\mathrm{term} \\ $$$$ \\ $$$$\left.\mathrm{1}\right).\:\:\frac{\mathrm{1}}{\mathrm{5}},\:\frac{\mathrm{1}}{\mathrm{4}}\:,\:\frac{\mathrm{3}}{\mathrm{11}},\:\frac{\mathrm{2}}{\mathrm{7}},… \\ $$$$\left.\mathrm{2}\right).\:\:\frac{\mathrm{3}}{\mathrm{5}},\:\frac{−\mathrm{9}}{\mathrm{11}}\:,\:\frac{−\mathrm{25}}{\mathrm{19}},\:\frac{\mathrm{57}}{\mathrm{35}},… \\ $$$$\left.\mathrm{3}\right).\:\:\:\frac{\mathrm{1}}{\mathrm{6}},\:\frac{\mathrm{7}}{\mathrm{11}}\:,\:\frac{\mathrm{13}}{\mathrm{16}},\:\frac{\mathrm{19}}{\mathrm{21}},… \\ $$$$\left.\mathrm{4}\right).\:\:\:\mathrm{4},−\:\frac{\mathrm{2}}{\mathrm{3}}\:,\:−\frac{\mathrm{4}}{\mathrm{13}},−\:\frac{\mathrm{1}}{\mathrm{5}},… \\ $$$$\left.\mathrm{5}\right).\:\:\mathrm{2},\:\mathrm{9}\:,\:\mathrm{28}\:,\:\mathrm{65},… \\ $$
Commented by Tony Lin last updated on 03/May/20
1)(1/5),(2/8),(3/(11)),(4/(14)),(5/(17))
$$\left.\mathrm{1}\right)\frac{\mathrm{1}}{\mathrm{5}},\frac{\mathrm{2}}{\mathrm{8}},\frac{\mathrm{3}}{\mathrm{11}},\frac{\mathrm{4}}{\mathrm{14}},\frac{\mathrm{5}}{\mathrm{17}} \\ $$
Commented by Tony Lin last updated on 03/May/20
3)(1/6),(7/(11)),((13)/(16)),((19)/(21)),((25)/(26))
$$\left.\mathrm{3}\right)\frac{\mathrm{1}}{\mathrm{6}},\frac{\mathrm{7}}{\mathrm{11}},\frac{\mathrm{13}}{\mathrm{16}},\frac{\mathrm{19}}{\mathrm{21}},\frac{\mathrm{25}}{\mathrm{26}} \\ $$
Commented by Tony Lin last updated on 03/May/20
5)1^3 +1, 2^3 +1, 3^3 +1 , 4^3 +1 , 5^3 +1=126
$$\left.\mathrm{5}\right)\mathrm{1}^{\mathrm{3}} +\mathrm{1},\:\mathrm{2}^{\mathrm{3}} +\mathrm{1},\:\mathrm{3}^{\mathrm{3}} +\mathrm{1}\:,\:\mathrm{4}^{\mathrm{3}} +\mathrm{1}\:,\:\mathrm{5}^{\mathrm{3}} +\mathrm{1}=\mathrm{126} \\ $$
Commented by zainal tanjung last updated on 03/May/20
thank you sir
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$
Commented by zainal tanjung last updated on 03/May/20
thank you sir
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$

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