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given-y-sin-pi-3-2x-2cos-pi-12-x-1-where-x-0-2pi-has-maximum-and-minimum-value-is-p-and-q-find-p-2-q-2-A-18-B-16-C-63-4-D-16-




Question Number 81354 by jagoll last updated on 12/Feb/20
given y = sin ((π/3)−2x)+2cos ((π/(12))+x)+1  where x ∈(0,2π) has maximum and  minimum value is p and q.  find p^2 −q^2  ?  (A) −18          (B) −16  (C) ((63)/4)                (D) 16
giveny=sin(π32x)+2cos(π12+x)+1wherex(0,2π)hasmaximumandminimumvalueispandq.findp2q2?(A)18(B)16(C)634(D)16
Commented by john santu last updated on 12/Feb/20
y = sin (−2x+(π/3))+2cos (x+(π/(12)))+1  sin (−2x+(π/3)) =cos ((π/2)−(−2x+(π/3)))  cos (2x+(π/6))=cos 2(x+(π/(12)))  let x+(π/(12)) = θ  y = cos 2θ+2cos θ+1  y = 2cos^2 θ+2cos θ  for cos θ=1 ⇒f_1  = 4 (max)  for cos θ=−1 ⇒f_2 = 0  for cos θ = −(1/2)⇒f_3 = 2×(1/4)+(−1)=−(1/2) (min)  p^2 −q^2  = (p+q)(p−q)= (7/2)×(9/2)=((63)/4)
y=sin(2x+π3)+2cos(x+π12)+1sin(2x+π3)=cos(π2(2x+π3))cos(2x+π6)=cos2(x+π12)letx+π12=θy=cos2θ+2cosθ+1y=2cos2θ+2cosθforcosθ=1f1=4(max)forcosθ=1f2=0forcosθ=12f3=2×14+(1)=12(min)p2q2=(p+q)(pq)=72×92=634
Commented by jagoll last updated on 12/Feb/20
thank you
thankyou

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