given-y-sin-pi-3-2x-2cos-pi-12-x-1-where-x-0-2pi-has-maximum-and-minimum-value-is-p-and-q-find-p-2-q-2-A-18-B-16-C-63-4-D-16- Tinku Tara June 4, 2023 Trigonometry 0 Comments FacebookTweetPin Question Number 81354 by jagoll last updated on 12/Feb/20 giveny=sin(π3−2x)+2cos(π12+x)+1wherex∈(0,2π)hasmaximumandminimumvalueispandq.findp2−q2?(A)−18(B)−16(C)634(D)16 Commented by john santu last updated on 12/Feb/20 y=sin(−2x+π3)+2cos(x+π12)+1sin(−2x+π3)=cos(π2−(−2x+π3))cos(2x+π6)=cos2(x+π12)letx+π12=θy=cos2θ+2cosθ+1y=2cos2θ+2cosθforcosθ=1⇒f1=4(max)forcosθ=−1⇒f2=0forcosθ=−12⇒f3=2×14+(−1)=−12(min)p2−q2=(p+q)(p−q)=72×92=634 Commented by jagoll last updated on 12/Feb/20 thankyou Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-146886Next Next post: 1-2-log-3-25-1-2-log-5-9- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.