Have-you-seen-this-method-of-solving-quadratic-problem-x-2-x-12-0-y-b-2-4ac-

Question Number 174950 by Mastermind last updated on 14/Aug/22

Have you seen this method of solving

quadratic problem ?

x^{2} - x - 12 = 0

y^{'} = \pm \sqrt{b^{2} - 4 ac}

Answered by peter frank last updated on 14/Aug/22

\frac{d}{dx} (x^{2} - x - 12) = \pm \sqrt{b^{2} - 4 ac}

2 x - 1 = \pm \sqrt{1^{2} - 4 \times - 12}

2 x - 1 = \pm \sqrt{1 + 48}

2 x - 1 = \pm \sqrt{49}

2 x - 1 = \pm 7

2 x = 1 \pm 7

x = \frac{1 \pm 7}{2}

Commented by Tawa11 last updated on 14/Aug/22

Great sir .

Commented by Tawa11 last updated on 14/Aug/22

x = \frac{1 \pm 7}{2}

x = 4 or - 3

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