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Question Number 100068 by  M±th+et+s last updated on 24/Jun/20
hello all i have some questions?    1)what is the riemann hypothesis?    2)how did they determine the distance  to the sun?    3)how did we measure the speed of light?
helloallihavesomequestions?1)whatistheriemannhypothesis?2)howdidtheydeterminethedistancetothesun?3)howdidwemeasurethespeedoflight?
Answered by JDamian last updated on 24/Jun/20
You can find the answers in google
Youcanfindtheanswersingoogle
Commented by  M±th+et+s last updated on 24/Jun/20
thank you for your comment sir.  but  in google there is no mathmatics   explaning just a simple explanation.
thankyouforyourcommentsir.butingooglethereisnomathmaticsexplaningjustasimpleexplanation.
Answered by smridha last updated on 25/Jun/20
 Maxwell diff:eq^n  said us  ▽^2 E^→ =𝛍_0 ε_0 (∂^2 E^→ /∂t^2 ) and ▽^2 B^→ =𝛍_0 𝛆_0 (∂^2 B^→ /∂t^2 )  where E^→ =electric field                   B^→ =magnetic field                   𝛍_0 =magnetic permiability in free space                    𝛆_0 =permitivity of free space  [this is besically 3d wave eq^n   this two eq^(ns)  describe light as  a electromagnetic wave]    now analysis the dimention of  the product of μ_0  and 𝛆_0 ..     dim[𝛆_0 𝛍_0 ]=[M^(−1) L^(−1) T^4 ].[ML^(−1) T^(−2) ]                     =[L^(−2) T^2 ]  now dim[(1/( (√(𝛍_0 𝛆_0 ))))]=[L.T^(−1) ]=dim(v)  where v=velocity but this not  any odinary velocity this is very  special, the speed of light in  free space denoted by C..  so our eq^n  looks like:  ▽^2 E^→ =(1/C^2 )(∂^2 E^→ /∂t^2 ) and ▽^2 B^→ =(1/C^2 ).(∂^2 B^→ /∂t^2 )  now speed of light:    C=(1/( (√(𝛍_0 𝛆_0 ))))=(1/( (√(4𝛑×10^(−7) ×8.854×10^(−12) ))))       =2.99795638×10^8 ≈3×10^8 m.s^(−1)   here I used the experimental value  of 𝛍_0  and 𝛆_0 .
Maxwelldiff:eqnsaidus2E=μ0ϵ02Et2and2B=μ0ϵ02Bt2whereE=electricfieldB=magneticfieldμ0=magneticpermiabilityinfreespaceϵ0=permitivityoffreespace[thisisbesically3dwaveeqnthistwoeqnsdescribelightasaelectromagneticwave]nowanalysisthedimentionoftheproductofμ0andϵ0..dim[ϵ0μ0]=[M1L1T4].[ML1T2]=[L2T2]nowdim[1μ0ϵ0]=[L.T1]=dim(v)wherev=velocitybutthisnotanyodinaryvelocitythisisveryspecial,thespeedoflightinfreespacedenotedbyC..sooureqnlookslike:2E=1C22Et2and2B=1C2.2Bt2nowspeedoflight:C=1μ0ϵ0=14π×107×8.854×1012=2.99795638×1083×108m.s1hereIusedtheexperimentalvalueofμ0andϵ0.
Commented by Rasheed.Sindhi last updated on 25/Jun/20
GO^(⌢) O^(⌢) D use of mathematical notation  in the field of human emotions!
GOODuseofmathematicalnotationinthefieldofhumanemotions!
Commented by  M±th+et+s last updated on 24/Jun/20
very nice explanation .  god bless you
veryniceexplanation.godblessyou
Commented by smridha last updated on 24/Jun/20
Σ_(i=1) ^∞ (thank)_i
i=1(thank)i
Commented by Rasheed.Sindhi last updated on 25/Jun/20
Can we consider   human-emotions-field  as a mathematical-field?  Of course, why not  if  we can define thanks,  sorry & other human-emotions!
Canweconsiderhumanemotionsfieldasamathematicalfield?Ofcourse,whynotifwecandefinethanks,sorry&otherhumanemotions!
Commented by smridha last updated on 25/Jun/20
yeah why not!!after all   Mathematics is nothing more than   a language.if there is a wish  there is a way..
yeahwhynot!!afterallMathematicsisnothingmorethanalanguage.ifthereisawishthereisaway..

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