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Hello-how-to-solve-this-equation-3x-y-1-5-x-2y-0-5-




Question Number 121567 by mathocean1 last updated on 09/Nov/20
Hello how to solve this   equation:   { ((3x−y≡1[5])),((x+2y≡0[5])) :}
$$\mathrm{Hello}\:\mathrm{how}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{this}\: \\ $$$$\mathrm{equation}: \\ $$$$\begin{cases}{\mathrm{3}{x}−{y}\equiv\mathrm{1}\left[\mathrm{5}\right]}\\{{x}+\mathrm{2}{y}\equiv\mathrm{0}\left[\mathrm{5}\right]}\end{cases} \\ $$
Commented by TANMAY PANACEA last updated on 09/Nov/20
[5]  what does [ .] means
$$\left[\mathrm{5}\right]\:\:{what}\:{does}\:\left[\:.\right]\:{means} \\ $$
Commented by mathocean1 last updated on 09/Nov/20
modulo
$$\mathrm{modulo} \\ $$$$ \\ $$
Answered by mr W last updated on 11/Nov/20
3x−y=5k+1  6x−2y=10k+2  x+2y=5h  7x=5(2k+h)+2  7(x−1)=5(2k+h−1)  ⇒x=5n+1  ⇒y=15n−5k+2
$$\mathrm{3}{x}−{y}=\mathrm{5}{k}+\mathrm{1} \\ $$$$\mathrm{6}{x}−\mathrm{2}{y}=\mathrm{10}{k}+\mathrm{2} \\ $$$${x}+\mathrm{2}{y}=\mathrm{5}{h} \\ $$$$\mathrm{7}{x}=\mathrm{5}\left(\mathrm{2}{k}+{h}\right)+\mathrm{2} \\ $$$$\mathrm{7}\left({x}−\mathrm{1}\right)=\mathrm{5}\left(\mathrm{2}{k}+{h}−\mathrm{1}\right) \\ $$$$\Rightarrow{x}=\mathrm{5}{n}+\mathrm{1} \\ $$$$\Rightarrow{y}=\mathrm{15}{n}−\mathrm{5}{k}+\mathrm{2} \\ $$

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