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help-3xdx-




Question Number 124542 by micelle last updated on 04/Dec/20
help  ∫3xdx
$${help}\:\:\int\mathrm{3}{xdx} \\ $$
Commented by bemath last updated on 04/Dec/20
∫ 3x dx = (6/2)∫ x dx = (9/3)∫x dx    = ((6x^2 )/4)+c = ((9x^2 )/6)+c
$$\int\:\mathrm{3}{x}\:{dx}\:=\:\frac{\mathrm{6}}{\mathrm{2}}\int\:{x}\:{dx}\:=\:\frac{\mathrm{9}}{\mathrm{3}}\int{x}\:{dx}\: \\ $$$$\:=\:\frac{\mathrm{6}{x}^{\mathrm{2}} }{\mathrm{4}}+{c}\:=\:\frac{\mathrm{9}{x}^{\mathrm{2}} }{\mathrm{6}}+{c}\: \\ $$
Answered by malwan last updated on 04/Dec/20
∫3xdx = 3(x^2 /2) + C
$$\int\mathrm{3}{xdx}\:=\:\mathrm{3}\frac{{x}^{\mathrm{2}} }{\mathrm{2}}\:+\:{C} \\ $$

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