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Help-A-beam-being-lifted-by-two-forces-where-F1makes-an-angle-of-23-degrees-with-the-y-axis-acts-in-the-second-quadrant-F2-acts-in-the-first-quadrant-making-an-angle-of-32-degrees-with-t




Question Number 183293 by neinhaltsieger369 last updated on 24/Dec/22
    Help!      A beam being lifted by two forces where    F1makes an angle of 23° degrees with the y   axis acts in the second quadrant F2 acts in   the first quadrant making an angle of 32°   degrees with the y axis and the resultant   force is 67 N, determine F1 and F2.
$$\: \\ $$$$\:\mathrm{Help}! \\ $$$$\: \\ $$$$\:\mathrm{A}\:\mathrm{beam}\:\mathrm{being}\:\mathrm{lifted}\:\mathrm{by}\:\mathrm{two}\:\mathrm{forces}\:\mathrm{where}\: \\ $$$$\:\mathrm{F1makes}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{23}°\:\mathrm{degrees}\:\mathrm{with}\:\mathrm{the}\:\mathrm{y} \\ $$$$\:\mathrm{axis}\:\mathrm{acts}\:\mathrm{in}\:\mathrm{the}\:\mathrm{second}\:\mathrm{quadrant}\:\mathrm{F2}\:\mathrm{acts}\:\mathrm{in} \\ $$$$\:\mathrm{the}\:\mathrm{first}\:\mathrm{quadrant}\:\mathrm{making}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{32}° \\ $$$$\:\mathrm{degrees}\:\mathrm{with}\:\mathrm{the}\:\mathrm{y}\:\mathrm{axis}\:\mathrm{and}\:\mathrm{the}\:\mathrm{resultant} \\ $$$$\:\mathrm{force}\:\mathrm{is}\:\mathrm{67}\:\mathrm{N},\:\mathrm{determine}\:\mathrm{F1}\:\mathrm{and}\:\mathrm{F2}. \\ $$$$\: \\ $$
Answered by mr W last updated on 24/Dec/22
Commented by mr W last updated on 24/Dec/22
i guess this is what you meant.  (F_1 /(sin 32°))=(F_2 /(sin 23°))=(F/(sin (32°+23°)))  ⇒F_1 =((sin 32°)/(sin 55°))×67≈43.3 N  ⇒F_2 =((sin 23°)/(sin 55°))×67≈31.9 N
$${i}\:{guess}\:{this}\:{is}\:{what}\:{you}\:{meant}. \\ $$$$\frac{{F}_{\mathrm{1}} }{\mathrm{sin}\:\mathrm{32}°}=\frac{{F}_{\mathrm{2}} }{\mathrm{sin}\:\mathrm{23}°}=\frac{{F}}{\mathrm{sin}\:\left(\mathrm{32}°+\mathrm{23}°\right)} \\ $$$$\Rightarrow{F}_{\mathrm{1}} =\frac{\mathrm{sin}\:\mathrm{32}°}{\mathrm{sin}\:\mathrm{55}°}×\mathrm{67}\approx\mathrm{43}.\mathrm{3}\:{N} \\ $$$$\Rightarrow{F}_{\mathrm{2}} =\frac{\mathrm{sin}\:\mathrm{23}°}{\mathrm{sin}\:\mathrm{55}°}×\mathrm{67}\approx\mathrm{31}.\mathrm{9}\:{N} \\ $$
Commented by neinhaltsieger369 last updated on 24/Dec/22
    Gracias
$$\: \\ $$$$\:\mathrm{Gracias} \\ $$

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