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Question Number 48724 by indalecioneves last updated on 29/Nov/18
Hey, everyone!  Could  someone help in this question below?  The vectors (1, 2, 5), (3, 2, 1) and (9, 2, −11) in R^3  generate the vector subspace to wich belongs the vector?  a) (−20, −8, 12)  b) (2, 10, 33)  c) (9, 10, 18)  d) (5, 2, −2)  e) (31, 18, 0)  Why are my posts never resolved?
$${Hey},\:{everyone}! \\ $$$${Could}\:\:{someone}\:{help}\:{in}\:{this}\:{question}\:{below}? \\ $$$${The}\:{vectors}\:\left(\mathrm{1},\:\mathrm{2},\:\mathrm{5}\right),\:\left(\mathrm{3},\:\mathrm{2},\:\mathrm{1}\right)\:{and}\:\left(\mathrm{9},\:\mathrm{2},\:−\mathrm{11}\right)\:{in}\:\mathbb{R}^{\mathrm{3}} \:{generate}\:{the}\:{vector}\:{subspace}\:{to}\:{wich}\:{belongs}\:{the}\:{vector}? \\ $$$$\left.{a}\right)\:\left(−\mathrm{20},\:−\mathrm{8},\:\mathrm{12}\right) \\ $$$$\left.{b}\right)\:\left(\mathrm{2},\:\mathrm{10},\:\mathrm{33}\right) \\ $$$$\left.{c}\right)\:\left(\mathrm{9},\:\mathrm{10},\:\mathrm{18}\right) \\ $$$$\left.{d}\right)\:\left(\mathrm{5},\:\mathrm{2},\:−\mathrm{2}\right) \\ $$$$\left.{e}\right)\:\left(\mathrm{31},\:\mathrm{18},\:\mathrm{0}\right) \\ $$$${Why}\:{are}\:{my}\:{posts}\:{never}\:{resolved}? \\ $$$$ \\ $$$$ \\ $$
Commented by ajfour last updated on 30/Nov/18
The subspace extends from x=1 to  x=9, y=2, z=−11 to z=5    taking min and max of   x,y,and z coordinates;  only (5,2,−2) belongs to this region.
$${The}\:{subspace}\:{extends}\:{from}\:{x}=\mathrm{1}\:{to} \\ $$$${x}=\mathrm{9},\:{y}=\mathrm{2},\:{z}=−\mathrm{11}\:{to}\:{z}=\mathrm{5} \\ $$$$\:\:{taking}\:{min}\:{and}\:{max}\:{of} \\ $$$$\:{x},{y},{and}\:{z}\:{coordinates}; \\ $$$${only}\:\left(\mathrm{5},\mathrm{2},−\mathrm{2}\right)\:{belongs}\:{to}\:{this}\:{region}. \\ $$
Answered by ajfour last updated on 29/Nov/18
d) (5,2,−2) .
$$\left.{d}\right)\:\left(\mathrm{5},\mathrm{2},−\mathrm{2}\right)\:. \\ $$
Commented by indalecioneves last updated on 30/Nov/18
Thank you, Sir!  But I ′d like of resolution, too.
$${Thank}\:{you},\:{Sir}! \\ $$$${But}\:{I}\:'{d}\:{like}\:{of}\:{resolution},\:{too}. \\ $$

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