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Question Number 50451 by JDlix last updated on 16/Dec/18
how can i derive a formula to calculate the speed of an electron  in n^(th)  orbit of a hydrogen atom?
howcanideriveaformulatocalculatethespeedofanelectroninnthorbitofahydrogenatom?
Answered by tanmay.chaudhury50@gmail.com last updated on 16/Dec/18
(1/(4πε_0 ))((e×e)/r_n ^2 )=((mv^2 )/r_n )  angular momentum=mvr_n =((nh)/(2π))  mv^2 r_n =ke^2    eqn  1      [k=(1/(4πε_0 ))]  mvr_n =((nh)/(2π))      eqn 2  deviding eqn 1 by eqn 2  v=((ke^2 )/(nh))×2π  v=(1/(4πε_0 ))×(e^2 /(nh))×2π=(e^2 /(2ε_0 h))×(1/n)  pls check....
14πϵ0e×ern2=mv2rnangularmomentum=mvrn=nh2πmv2rn=ke2eqn1[k=14πϵ0]mvrn=nh2πeqn2devidingeqn1byeqn2v=ke2nh×2πv=14πϵ0×e2nh×2π=e22ϵ0h×1nplscheck.
Commented by peter frank last updated on 16/Dec/18
your right  i get the same   result
yourrightigetthesameresult
Answered by peter frank last updated on 16/Dec/18
Commented by JDlix last updated on 17/Dec/18
i want to thank both of u
iwanttothankbothofu

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