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Question Number 13327 by Nayon last updated on 18/May/17
how can we expand (1+x)^(1/2) ??
howcanweexpand(1+x)12??
Answered by prakash jain last updated on 19/May/17
(1+x)^y =1+yx+((y(y−1))/(2!))x^2 +((y(y−1)(y−2))/(3!))x^3 +                ...  to infinity  The above series expansion  is valid for ∣x∣<1 (for convergence)  (1+x)^(1/2) =1+(1/2)x+(((1/2)((1/2)−1))/(2!))x^2 +...
(1+x)y=1+yx+y(y1)2!x2+y(y1)(y2)3!x3+toinfinityTheaboveseriesexpansionisvalidforx∣<1(forconvergence)(1+x)1/2=1+12x+12(121)2!x2+

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