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Question Number 34382 by rashedul last updated on 05/May/18
how do i prove  ∫_o ^t cos 2(ωt+α)dt=0
howdoiproveotcos2(ωt+α)dt=0
Answered by tanmay.chaudhury50@gmail.com last updated on 05/May/18
=((∣sin(2wt+2α)∣_0 ^T )/(2w))  =((sin(2wT+2α)−sin(2α))/(2w))  w=((2Π)/T) so    =((sin(4Π+2α)−sin2α)/(2ω))  =((sin2α−sin2α)/(2w))  =0  i think upper limig of intregal is T where T  T=2Π/w
=sin(2wt+2α)T02w=sin(2wT+2α)sin(2α)2ww=2ΠTso=sin(4Π+2α)sin2α2ω=sin2αsin2α2w=0ithinkupperlimigofintregalisTwhereTT=2Π/w

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