How-long-does-it-take-for-the-disintegration-of-3-10-of-an-atom-with-radioactive-constant-

Question Number 116238 by Ar Brandon last updated on 02/Oct/20

How long does it take for the disintegration of

\frac{3}{10} of an atom with radioactive constant λ ?

Answered by MrGaster last updated on 22/Jan/25

N (t) = N_{0} e^{- λ t}

\frac{3}{10} N_{0} = N_{0} e^{- λ t}

\frac{3}{10} = e^{- λ t}

\ln (\frac{3}{10}) = - λ t

t = - \frac{\ln (\frac{3}{10})}{λ}

t = \frac{\ln (\frac{10}{3})}{λ}

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