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How-many-3-digit-numbers-divisible-by-5-can-be-made-using-the-numbers-7-8-9-2-1-0-without-repetition-




Question Number 125182 by Mammadli last updated on 08/Dec/20
How many 3−digit numbers divisible by 5 can be made using the numbers 7,8,9,2,1,0 without repetition?
Howmany3digitnumbersdivisibleby5canbemadeusingthenumbers7,8,9,2,1,0withoutrepetition?
Answered by bemath last updated on 08/Dec/20
AB0 ⇒ P_2 ^( 5)  = ((5!)/(3!)) = 20.
AB0P25=5!3!=20.

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