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How-many-4-letters-word-can-be-formed-from-COMMUNICATION-




Question Number 130019 by I want to learn more last updated on 21/Jan/21
How many 4 letters word can be formed from    COMMUNICATION
Howmany4letterswordcanbeformedfromCOMMUNICATION
Answered by mr W last updated on 22/Jan/21
2×C  2×O  2×M  2×N  2×I  1×U  1×A  1×T    case 1: WXYZ  4!(1+x)^5 (1+x)^3 =...1680x^4 ...  or C_4 ^8 ×4!=1680    case 2: XYYZ  ((4!)/(2!))×C_1 ^5 ×x^2 (1+x)^4 (1+x)^3 =...1260x^4 ...  or C_1 ^5 ×C_2 ^7 ×((4!)/(2!))=1260    case 3: XXYY  ((4!)/(2!2!))×C_2 ^5 ×x^2 ×x^2 (1+x)^3 (1+x)^3 =...60x^4 ...  or C_2 ^5 ×((4!)/(2!2!))=60    total 1680+1260+60=3000 words
2×C2×O2×M2×N2×I1×U1×A1×Tcase1:WXYZ4!(1+x)5(1+x)3=1680x4orC48×4!=1680case2:XYYZ4!2!×C15×x2(1+x)4(1+x)3=1260x4orC15×C27×4!2!=1260case3:XXYY4!2!2!×C25×x2×x2(1+x)3(1+x)3=60x4orC25×4!2!2!=60total1680+1260+60=3000words
Commented by I want to learn more last updated on 22/Jan/21
Thanks sir, i appreciate.
Thankssir,iappreciate.
Commented by I want to learn more last updated on 23/Jan/21
Sir that is coefficient of   x^4   in    4!(1  +  (x/(1!))  +  (x^2 /(2!)))^5 (1  +  x)^3   Thanks sir
Sirthatiscoefficientofx4in4!(1+x1!+x22!)5(1+x)3Thankssir
Commented by mr W last updated on 23/Jan/21
yes.
yes.
Commented by I want to learn more last updated on 23/Jan/21
Thanks sir.
Thankssir.
Commented by mr W last updated on 24/Jan/21
see also Q130193
seealsoQ130193

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