How-many-6-digit-odd-numbers-have-different-digits-

Question Number 124237 by mr W last updated on 01/Dec/20

H o w m a n y 6 d i g i t o d d n u m b e r s h a v e

d i f f e r e n t d i g i t s ?

Commented by mr W last updated on 02/Dec/20

5 \times (P_{5}^{9} - P_{4}^{8}) = 67200

Answered by liberty last updated on 01/Dec/20

c a s e (1) A B w h e r e A a n d B o d d n u m b e r

= 5 \times P_{4}^{8} \times 4

c a s e (2) A B w h e r e A e v e n a n d B o d d n u m b e r

= 4 \times P_{4}^{8} \times 5

t o t a l l y = P_{4}^{8} \times 40 = \frac{8 \times 7 \times 6 \times 5 \times 4!}{4!} \times 40

= 56 \times 30 \times 40 = 67200

56 \times 30 \times 40

67200.0

Commented by mr W last updated on 02/Dec/20

c o r r e c t s i r, t h a n k s!

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