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Question Number 176774 by Ar Brandon last updated on 26/Sep/22
How many distinct y exist satisfying  ∣x^2 −8x+18∣+∣y−3∣=5
Howmanydistinctyexistsatisfyingx28x+18+y3∣=5
Answered by mr W last updated on 26/Sep/22
x,y∈Z  ∣(x−4)^2 +2∣+∣y−3∣=5  2+∣y−3∣=5 ⇒y−3=±3 ⇒y=0, 6  3+∣y−3∣=5 ⇒y−3=±2 ⇒y=1, 5  4 dictinct values of y exist.
x,yZ(x4)2+2+y3∣=52+y3∣=5y3=±3y=0,63+y3∣=5y3=±2y=1,54dictinctvaluesofyexist.
Commented by Ar Brandon last updated on 27/Sep/22
Thank you Sir. I now get it.
Commented by mr W last updated on 27/Sep/22
∣(x−4)^2 +2∣+∣y−3∣=5  let t=x−4  ∣t^2 +2∣+∣y−3∣=5  t^2  can only be 0, 1, 4, 9, 16 etc.  ∣t^2 +2∣ can only be 2, 3, 6, 11, 18 etc.  with ∣t^2 +2∣=2 you get 2+∣y−3∣=5.  with ∣t^2 +2∣=3 you get 3+∣y−3∣=5.  with ∣t^2 +2∣=6 you get 6+∣y−3∣=5 ⇒no solution!
(x4)2+2+y3∣=5lett=x4t2+2+y3∣=5t2canonlybe0,1,4,9,16etc.t2+2canonlybe2,3,6,11,18etc.witht2+2∣=2youget2+y3∣=5.witht2+2∣=3youget3+y3∣=5.witht2+2∣=6youget6+y3∣=5nosolution!
Commented by Ar Brandon last updated on 26/Sep/22
Great! Thank you, Sir!
Commented by Ar Brandon last updated on 27/Sep/22
Sir why  2+∣y−3∣ and 3+∣y−3∣ ?
Sirwhy2+y3and3+y3?

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