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Question Number 100130 by bemath last updated on 25/Jun/20
how many integer number   satisfy the equation   ((sin x−∣x+2∣)/(x^2 −4x−5)) ≥ 0
howmanyintegernumbersatisfytheequationsinxx+2x24x50
Answered by mr W last updated on 25/Jun/20
let f(x)=sin x −∣x+2∣  for x≤−2:  f(x)=sin x+x+2  f′(x)=cos x+1≥0 ⇒increasing  f(x)≤f(−2)=sin (−2)≈−0.909    for x≥−2:  f(x)=sin x−x−2  f′(x)=cos x−1≤0 ⇒decreasing  f(x)≤f(−2)=sin (−2)≈−0.909    ⇒f(x)=sin x−∣x+2∣≤sin (−2)≈−0.909<0    ((sin x−∣x+2∣)/(x^2 −4x−5)) ≥ 0   since always sin x−∣x+2∣<0  ⇒x^2 −4x−5<0  i.e. (x+1)(x−5)<0  ⇒−1<x<5  ⇒x=0,1,2,3,4 ⇒5 integers
letf(x)=sinxx+2forx2:f(x)=sinx+x+2f(x)=cosx+10increasingf(x)f(2)=sin(2)0.909forx2:f(x)=sinxx2f(x)=cosx10decreasingf(x)f(2)=sin(2)0.909f(x)=sinxx+2∣⩽sin(2)0.909<0sinxx+2x24x50sincealwayssinxx+2∣<0x24x5<0i.e.(x+1)(x5)<01<x<5x=0,1,2,3,45integers
Commented by Rasheed.Sindhi last updated on 25/Jun/20
T_(H_A  N) k_(S  )       S_I  R        !
THANkSSIR!
Commented by bobhans last updated on 26/Jun/20
cooll great
coollgreat

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