how-many-odd-numbers-greater-than-60000-can-be-made-from-the-digits-5-6-7-8-9-0-if-no-number-contains-any-digit-more-than-once- Tinku Tara June 4, 2023 Permutation and Combination 0 Comments FacebookTweetPin Question Number 43343 by pieroo last updated on 10/Sep/18 howmanyoddnumbersgreaterthan60000canbemadefromthedigits5,6,7,8,9,0ifnonumbercontainsanydigitmorethanonce? Answered by tanmay.chaudhury50@gmail.com last updated on 10/Sep/18 −5−4−3−2−1digitsare5,6,7,8,9,0(sixnosofdigit)numbersgreaterthan60,000…the5thplacecanbefilledby(6,7,8,9)numbersareoddso1stplacecanbefilled(5,7,9)1)−65−4−3−2−515thplacefilledby6and1stplaceby54thplacecanbefilledbyanydigitoutof(7,8,9,0)so4ways3rdplacecanbefilledbyanyremainingthreedigitso3ways2ndplacecanbefilledbyanyremainingtwodigitso2waysThusthenumberswhose1stplaceis5and5thplaceis6thatmeansgreaterthan60000butoddare4×3×2=24−65−×4−×3−×2−51→24−65−×4−×3−×2−71→24−65−×4−×3−×2−91−24thus24×3=72−75−×4−×3−×2−51→24−75−×4−×3−×2−91→24−85−×4−×3−×2−51→24−85−×4−×3−×2−71→24−85−×4−×3−×2−91→24−95−×4−×3−×2−51→24−95−×4−×3−×2−71→245thplace6→24×3=725thplacd7→24×2=485thplace8→24×3=725thplace9→24×2=48total=72+48+72+48=240 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: using-the-substitution-u-x-2-evaluate-1-2-x-1-x-2-4-Next Next post: sin-x-sin-5x-sin-3x-find-the-angle-that-satisfied-the-equestion- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.