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How-many-odd-numbers-greater-than-60000-can-be-made-from-the-digits-5-6-7-8-9-0-if-no-number-contains-any-digit-more-than-ones-




Question Number 56688 by pieroo last updated on 21/Mar/19
How many odd numbers, greater than  60000, can be made from the digits  5,6,7,8,9,0, if no number contains any  digit more than ones?
Howmanyoddnumbers,greaterthan60000,canbemadefromthedigits5,6,7,8,9,0,ifnonumbercontainsanydigitmorethanones?
Answered by mr W last updated on 22/Mar/19
6XXXY, 8XXXY: 2×3×P_3 ^( 4)   7XXXY, 9XXXY: 2×2×P_3 ^( 4)   ZXXXXY: 3×4×4!    ⇒(2×3+2×2)P_3 ^( 4) +3×4×4!=528
6XXXY,8XXXY:2×3×P347XXXY,9XXXY:2×2×P34ZXXXXY:3×4×4!(2×3+2×2)P34+3×4×4!=528
Commented by malwaan last updated on 22/Mar/19
I dont understant  please more explainasion
Idontunderstantpleasemoreexplainasion
Commented by rahul 19 last updated on 22/Mar/19
 6 −_↓_(4ways)   −_↓_(3ways)   −_↓_(2ways)   −_↓_(^3 C_1 )    similarly for digits starting with  8.  7 −_↓_(4ways)   −_↓_(3ways)   −_↓_(2ways)   −_↓_(^2 C_1 ^ )     Similarly for digits starting with 9.       ⇒ 2(4×3×2×3)+2(4×3×2×2)=240.  (Dear pieroo,  in this sol^(n )  i′ve counted 5−digit no.s  only! So this sol^n  is incomplete.)
64ways3ways2ways3C1similarlyfordigitsstartingwith8.74ways3ways2ways2C1Similarlyfordigitsstartingwith9.2(4×3×2×3)+2(4×3×2×2)=240.(Dearpieroo,inthissolnivecounted5digitno.sonly!Sothissolnisincomplete.)
Commented by mr W last updated on 22/Mar/19
this is correct for 5−digit numbers.  but you can also make 6−digit numbers.  they are all greater than 60000.
thisiscorrectfor5digitnumbers.butyoucanalsomake6digitnumbers.theyareallgreaterthan60000.
Commented by mr W last updated on 22/Mar/19
with the 6 digits we can make 5−digit  numbers (like 78065) and 6−digit  numbers (like 567809).    5−digit numbers greater than 6000:  6 XXX Y: Y can be 5,7,9 ⇒3 ways, XXX from the remaining 4 digits⇒P_3 ^( 4)  ways, totally 3×P_3 ^( 4)  ways.  8 XXX Y: as 6XXXY, totally 3×P_3 ^( 4)  ways.  7 XXX Y: Y can be 5,9 ⇒2 ways, XXX from the remaining 4 digits⇒P_3 ^( 4)  ways, totally 2×P_3 ^( 4)  ways.  8 XXX Y: as 7XXXY, totally 2×P_3 ^( 4)  ways.  ⇒5−digit numbers: 2×3×P_3 ^( 4) +2×2×P_3 ^( 4) =240    6−digit numbers:  ZXXXXY:  Y can be 5,7,9⇒ 3 ways  Z can be one of the 4 remaining (0 not allowed) ⇒4 ways  XXXX from the 4 remaining digits⇒4! ways  ⇒6−digit numbers: 3×4×4!=288    all possible numbers: 240+288=528
withthe6digitswecanmake5digitnumbers(like78065)and6digitnumbers(like567809).5digitnumbersgreaterthan6000:6XXXY:Ycanbe5,7,93ways,XXXfromtheremaining4digitsP34ways,totally3×P34ways.8XXXY:as6XXXY,totally3×P34ways.7XXXY:Ycanbe5,92ways,XXXfromtheremaining4digitsP34ways,totally2×P34ways.8XXXY:as7XXXY,totally2×P34ways.5digitnumbers:2×3×P34+2×2×P34=2406digitnumbers:ZXXXXY:Ycanbe5,7,93waysZcanbeoneofthe4remaining(0notallowed)4waysXXXXfromthe4remainingdigits4!ways6digitnumbers:3×4×4!=288allpossiblenumbers:240+288=528
Commented by rahul 19 last updated on 22/Mar/19
Thank You Sir! :)
ThankYouSir!:)
Commented by malwaan last updated on 28/Mar/19
thank you so much sir
thankyousomuchsir

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