Menu Close

How-many-pairs-of-integers-x-and-y-satisfy-the-equation-1-x-1-y-1-32-




Question Number 110592 by Aina Samuel Temidayo last updated on 29/Aug/20
How many pairs of integers x and y  satisfy the equation (1/x)+(1/y)=(1/(32))
Howmanypairsofintegersxandysatisfytheequation1x+1y=132
Answered by Aziztisffola last updated on 29/Aug/20
 if x=y ⇒ (2/x)=(1/(32))⇒x=64   (x;y)=(64;64) ∈S then S≠∅  there is at least one solution.
ifx=y2x=132x=64(x;y)=(64;64)SthenSthereisatleastonesolution.
Answered by mr W last updated on 29/Aug/20
(1/y)=(1/(32))−(1/x)=((x−32)/(32x))  y=((32x)/(x−32))  x=33 ⇒y=1056  x=34 ⇒y=544  x=36 ⇒y=288  x=40 ⇒y=160  x=48 ⇒y=96  x=64 ⇒y=64  x=31 ⇒y=−993  x=30 ⇒y=−480  x=28 ⇒y=−224  x=24 ⇒y=−96  x=16 ⇒y=−32  ......
1y=1321x=x3232xy=32xx32x=33y=1056x=34y=544x=36y=288x=40y=160x=48y=96x=64y=64x=31y=993x=30y=480x=28y=224x=24y=96x=16y=32
Commented by Aina Samuel Temidayo last updated on 29/Aug/20
Thanks but how did you know the values of (x,y)  that fits the equation? Your work is  not well explanatory.
Thanksbuthowdidyouknowthevaluesof(x,y)thatfitstheequation?Yourworkisnotwellexplanatory.
Commented by mr W last updated on 29/Aug/20
if x−32 divides 32, then x is ok.  ⇒x−32=±1,±2,±4,±8,±16,±32
ifx32divides32,thenxisok.x32=±1,±2,±4,±8,±16,±32
Answered by floor(10²Eta[1]) last updated on 29/Aug/20
go see my answer on Q.103093  it′s the same logic
goseemyansweronQ.103093itsthesamelogic
Commented by Aina Samuel Temidayo last updated on 29/Aug/20
Thanks.
Thanks.

Leave a Reply

Your email address will not be published. Required fields are marked *