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Question Number 111724 by Aina Samuel Temidayo last updated on 04/Sep/20
How many real numbers x satisfy the  equation 3^(2x+2) −3^(x+3) −3^x +3=0 ?
Howmanyrealnumbersxsatisfytheequation32x+23x+33x+3=0?
Commented by mohammad17 last updated on 05/Sep/20
3^(2x) .3^2 −3^x .3^3 −3^x +3=0    set: k=3^x     9k^2 −28k+3=0    k=((−b∓(√(b^2 −4ac)))/(2a))⇒k=((28∓(√(784−108)))/(18))    k=((28∓(√(676)))/(18))⇒k=((28∓26)/(18))    either:k=(2/(18))⇒k=(1/9)⇒3^x =(1/9)⇒x=((ln((1/9)))/(ln(3)))⇒x=−2     or:k=((54)/(18))⇒k=3⇒3^x =3⇒x=1    ∴x=1 is true    by:≪mohammad ≫
32x.323x.333x+3=0set:k=3x9k228k+3=0k=bb24ac2ak=2878410818k=2867618k=282618either:k=218k=193x=19x=ln(19)ln(3)x=2or:k=5418k=33x=3x=1x=1istrueby:≪mohammad
Commented by Aina Samuel Temidayo last updated on 05/Sep/20
Thanks.
Thanks.
Commented by Her_Majesty last updated on 05/Sep/20
why do you cancel x=−2? it′s a real number  and it′s a solution.
whydoyoucancelx=2?itsarealnumberanditsasolution.
Commented by mohammad17 last updated on 05/Sep/20
im,sory sir am missed
im,sorysirammissed
Commented by mohammad17 last updated on 05/Sep/20
you are welcome but sir x=−2 and x=1
youarewelcomebutsirx=2andx=1
Commented by Her_Majesty last updated on 05/Sep/20
now it′s right!
nowitsright!

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