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How-many-seven-letter-words-can-be-formed-by-using-the-letters-of-the-word-SUCCESS-so-that-neither-two-C-nor-two-S-are-together-




Question Number 21917 by Tinkutara last updated on 06/Oct/17
How many seven letter words can be  formed by using the letters of the word  SUCCESS so that neither two C nor  two S are together?
HowmanysevenletterwordscanbeformedbyusingthelettersofthewordSUCCESSsothatneithertwoCnortwoSaretogether?
Commented by mrW1 last updated on 07/Oct/17
S must be separated by other 4 letters:  YXYXYXYXY  (X means positions for letters UCCE,   Y means possible positions for letter S)  to arrange the 4 letters UCCE in positions  X there are 4!/2! ways, to place 3 letters  S in positions Y there are C_3 ^5  ways  ⇒4!/2!×C_3 ^5   (2! since letter C repeats twice)    note: in some of these ways the two  letters C are next to each other. to  find the number of ways where two  C are next to each other, we can   proceed as above, but treat CC as a  single letter. that means   YXYXYXY  ⇒3!×C_3 ^4     ⇒the number of ways such that neither  two S nor two C are next to each other is:  4!/2!×C_3 ^5 −3!×C_3 ^4 =24/2×10−6×4=96
Smustbeseparatedbyother4letters:YXYXYXYXY(XmeanspositionsforlettersUCCE,YmeanspossiblepositionsforletterS)toarrangethe4lettersUCCEinpositionsXthereare4!/2!ways,toplace3lettersSinpositionsYthereareC35ways4!/2!×C35(2!sinceletterCrepeatstwice)note:insomeofthesewaysthetwolettersCarenexttoeachother.tofindthenumberofwayswheretwoCarenexttoeachother,wecanproceedasabove,buttreatCCasasingleletter.thatmeansYXYXYXY3!×C34thenumberofwayssuchthatneithertwoSnortwoCarenexttoeachotheris:4!/2!×C353!×C34=24/2×106×4=96
Commented by Tinkutara last updated on 07/Oct/17
Thank you very much Sir!
ThankyouverymuchSir!
Commented by mrW1 last updated on 07/Oct/17
I′m interessed what is the solution in  your book.
Iminteressedwhatisthesolutioninyourbook.
Commented by Tinkutara last updated on 07/Oct/17
It does not explain much.
Itdoesnotexplainmuch.

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