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How-many-three-digit-numbers-can-be-formed-using-the-digits-2-3-5-7-8-if-the-number-is-odd-and-no-digit-is-repeted-




Question Number 153714 by pete last updated on 09/Sep/21
How many three−digit numbers can be  formed using the digits 2,3,5,7,8 if   the number is odd and no digit is repeted?
Howmanythreedigitnumberscanbeformedusingthedigits2,3,5,7,8ifthenumberisoddandnodigitisrepeted?
Answered by EDWIN88 last updated on 09/Sep/21
= P_1 ^( 3) ×P_2 ^( 4)  =((3!)/(2!))×((4!)/(2!)) = 6×6=36
=P13×P24=3!2!×4!2!=6×6=36
Answered by puissant last updated on 09/Sep/21
A_3 ^1 ×A_4 ^2 =((3!)/((3−1)!))×((4!)/((4−2)!))  =3×4×3  =36..
A31×A42=3!(31)!×4!(42)!=3×4×3=36..

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