Question Number 92340 by jagoll last updated on 06/May/20
$$\underset{\mathrm{i}\:=\:\mathrm{1}} {\overset{\infty} {\prod}}\:\frac{\mathrm{5}^{\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{i}} } +\mathrm{3}^{\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{i}} } }{\mathrm{2}}\:=\: \\ $$
Commented by john santu last updated on 06/May/20
$$=\:\frac{\mathrm{2}}{\mathrm{ln}\left(\mathrm{5}\right)−\mathrm{ln}\left(\mathrm{3}\right)}\:=\:\frac{\mathrm{2}}{\mathrm{ln}\left(\frac{\mathrm{5}}{\mathrm{3}}\right)}\: \\ $$
Commented by jagoll last updated on 06/May/20
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