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i-1-i-xi-i-x-x-




Question Number 153682 by EDWIN88 last updated on 09/Sep/21
 ((i)^(1/i)  )^(xi)  = i^x      x=?
(ii)xi=ixx=?
Answered by MJS_new last updated on 09/Sep/21
lhs i=e^(i(π/2))  ⇒ (i)^(1/i) =e^(π/2)  ⇒ ((i)^(1/i) )^(ix) =e^(i((xπ)/2))   rhs i^x =e^(i((xπ)/2))   ⇒ x∈C
lhsi=eiπ2ii=eπ2(ii)ix=eixπ2rhsix=eixπ2xC

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