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I-1-x-x-x-2-dx-I-1-x-x-x-dx-I-1-x-x-x-2-2-dx-I-1-4-x-4x-2-x-dx-I-2-1-1-2-x-2-1-




Question Number 182954 by Gamil last updated on 17/Dec/22
 I=∫ (1/( (√(x (√x) −x^2 )))) dx     I=∫ (1/(  ∙  (√(x((√x) −x))))) dx    I=∫ (1/( (√x) ∙ (√((√x) −x)) )) ×(2/2) dx   I= ∫ (1/( (√(4(√x) −4x)))) ∙ (2/( (√x))) dx    I=2∫ ( /( (√(1−(1−2 (√x))^2 )))) ∙ (1/( (√x))) dx     I= −2∫ (1/( (√(1−(1−2(√x))^2 ))))  ∙ d(1−2(√x))    I= −2sin^(−1) (1−2(√x)) +C          Gamil AL mansob
I=1xxx2dxI=1x(xx)dxI=1xxx×22dxI=14x4x2xdxI=21(12x)21xdxI=211(12x)2d(12x)I=2sin1(12x)+CGamilALmansob
Commented by Rasheed.Sindhi last updated on 17/Dec/22
  Question should go in place of Question._(AND^( ) )     Answer should go in place of Answer.
QuestionshouldgoinplaceofQuestion.ANDAnswershouldgoinplaceofAnswer.

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