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I-incenter-AB-BE-CF-internal-bisectors-in-ABC-Prove-that-8-AI-DI-BI-EI-CI-FI-4R-r-

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Question Number 172694 by Shrinava last updated on 30/Jun/22
I-incenter AB , BE , CF-internal bisectors in △ABC Prove that 8 ≤ ((AI)/(DI)) ∙ ((BI)/(EI)) ∙ ((CI)/(FI)) ≤ ((4R)/r)
I−incenterAB,BE,CF−internalbisectorsin△ABCProvethat8⩽AIDI⋅BIEI⋅CIFI⩽4Rr

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