I-pi-6-pi-3-sin-2021-x-sin-2021-x-cos-2021-x-dx- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 144282 by SOMEDAVONG last updated on 24/Jun/21 I=∫π6π3sin2021xsin2021x+cos2021xdx=? Answered by som(math1967) last updated on 24/Jun/21 I=∫π6π3sin2021(π3+π6−x)sin2021(π3+π6−x)+cos(π3+π6−x)dxI=∫π6π3cos2021xsin2021x+cos2021xdx∴2I=∫π6π3cos2021x+sin2021xsin2021x+cos2021xdx2I=∫π6π3dxI=[x2]π6π3=π12ans Commented by SOMEDAVONG last updated on 24/Jun/21 Thankssir! Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-144273Next Next post: Question-144291 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.