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Question Number 36080 by Rio Mike last updated on 28/May/18
 i want to know how   α^2 + β^2 = (α+β)^2 − 2αβ why not   α^2 +β^2 = (α+β)^2 + 2αβ?
iwanttoknowhowα2+β2=(α+β)22αβwhynotα2+β2=(α+β)2+2αβ?
Commented by Joel579 last updated on 29/May/18
α^2  + β^2  = (α + β)^2  − 2αβ                   = (α − β)^2  + 2αβ
α2+β2=(α+β)22αβ=(αβ)2+2αβ
Answered by tanmay.chaudhury50@gmail.com last updated on 28/May/18
value of (α+β)^2 −2αβ  =α^2 +2αβ+β^2 −2αβ  =α^2 +β^2   value of (α+β)^2 +2αβ  =α^2 +2αβ+β^2 +2αβ  =α^2 +β^2 +4αβ  that is why...
valueof(α+β)22αβ=α2+2αβ+β22αβ=α2+β2valueof(α+β)2+2αβ=α2+2αβ+β2+2αβ=α2+β2+4αβthatiswhy
Answered by Rasheed.Sindhi last updated on 28/May/18
α^2 + β^2                =α^2 +2αβ+ β^2 −2αβ               =(α+β)^2 −2αβ
α2+β2=α2+2αβ+β22αβ=(α+β)22αβ

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