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Question Number 181140 by Acem last updated on 22/Nov/22
I watch a favorite TV program daily for 30 min.   If there were ads every 3 hours, what′s the   probability that i will see ads once again the next   day while watching that program?
$${I}\:{watch}\:{a}\:{favorite}\:{TV}\:{program}\:{daily}\:{for}\:\mathrm{30}\:{min}. \\ $$$$\:{If}\:{there}\:{were}\:{ads}\:{every}\:\mathrm{3}\:{hours},\:{what}'{s}\:{the} \\ $$$$\:{probability}\:{that}\:{i}\:{will}\:{see}\:{ads}\:{once}\:{again}\:{the}\:{next} \\ $$$$\:{day}\:{while}\:{watching}\:{that}\:{program}? \\ $$$$ \\ $$
Commented by mr W last updated on 22/Nov/22
p=(8/(48))=(1/6) ?
$${p}=\frac{\mathrm{8}}{\mathrm{48}}=\frac{\mathrm{1}}{\mathrm{6}}\:? \\ $$
Commented by Acem last updated on 22/Nov/22
Yes Sir!
$${Yes}\:{Sir}! \\ $$
Commented by Acem last updated on 22/Nov/22
We make 3 hours as 6 domains for the 30 minutes   represent one domain, the probab. of the event    occurring is one of these 6 domains.  well, please show me your method
$${We}\:{make}\:\mathrm{3}\:{hours}\:{as}\:\mathrm{6}\:{domains}\:{for}\:{the}\:\mathrm{30}\:{minutes} \\ $$$$\:{represent}\:{one}\:{domain},\:{the}\:{probab}.\:{of}\:{the}\:{event}\: \\ $$$$\:{occurring}\:{is}\:{one}\:{of}\:{these}\:\mathrm{6}\:{domains}. \\ $$$${well},\:{please}\:{show}\:{me}\:{your}\:{method} \\ $$
Commented by Acem last updated on 22/Nov/22
It seems that the 48 represent 2 days and the 8   represent number of times ads per day,   right or something else?
$${It}\:{seems}\:{that}\:{the}\:\mathrm{48}\:{represent}\:\mathrm{2}\:{days}\:{and}\:{the}\:\mathrm{8} \\ $$$$\:{represent}\:{number}\:{of}\:{times}\:{ads}\:{per}\:{day}, \\ $$$$\:{right}\:{or}\:{something}\:{else}? \\ $$
Commented by mr W last updated on 22/Nov/22
i divide one day (24h) into 48 equal  sections with length 30 min for each.  the ads come every 3 hours, that means  8 times every day. that means: in 8  of the 48 sections there are ads.   when we watch TV for 30 min in a   day,  we take one from the 48   sections, so the probability that it has   ads is (8/(48))=(1/6).
$${i}\:{divide}\:{one}\:{day}\:\left(\mathrm{24}{h}\right)\:{into}\:\mathrm{48}\:{equal} \\ $$$${sections}\:{with}\:{length}\:\mathrm{30}\:{min}\:{for}\:{each}. \\ $$$${the}\:{ads}\:{come}\:{every}\:\mathrm{3}\:{hours},\:{that}\:{means} \\ $$$$\mathrm{8}\:{times}\:{every}\:{day}.\:{that}\:{means}:\:{in}\:\mathrm{8} \\ $$$${of}\:{the}\:\mathrm{48}\:{sections}\:{there}\:{are}\:{ads}.\: \\ $$$${when}\:{we}\:{watch}\:{TV}\:{for}\:\mathrm{30}\:{min}\:{in}\:{a}\: \\ $$$${day},\:\:{we}\:{take}\:{one}\:{from}\:{the}\:\mathrm{48}\: \\ $$$${sections},\:{so}\:{the}\:{probability}\:{that}\:{it}\:{has}\: \\ $$$${ads}\:{is}\:\frac{\mathrm{8}}{\mathrm{48}}=\frac{\mathrm{1}}{\mathrm{6}}. \\ $$
Commented by Acem last updated on 22/Nov/22
That′s good, thank you for sharing
$${That}'{s}\:{good},\:{thank}\:{you}\:{for}\:{sharing} \\ $$

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