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Question Number 181140 by Acem last updated on 22/Nov/22
I watch a favorite TV program daily for 30 min.   If there were ads every 3 hours, what′s the   probability that i will see ads once again the next   day while watching that program?
IwatchafavoriteTVprogramdailyfor30min.Iftherewereadsevery3hours,whatstheprobabilitythatiwillseeadsonceagainthenextdaywhilewatchingthatprogram?
Commented by mr W last updated on 22/Nov/22
p=(8/(48))=(1/6) ?
p=848=16?
Commented by Acem last updated on 22/Nov/22
Yes Sir!
YesSir!
Commented by Acem last updated on 22/Nov/22
We make 3 hours as 6 domains for the 30 minutes   represent one domain, the probab. of the event    occurring is one of these 6 domains.  well, please show me your method
Wemake3hoursas6domainsforthe30minutesrepresentonedomain,theprobab.oftheeventoccurringisoneofthese6domains.well,pleaseshowmeyourmethod
Commented by Acem last updated on 22/Nov/22
It seems that the 48 represent 2 days and the 8   represent number of times ads per day,   right or something else?
Itseemsthatthe48represent2daysandthe8representnumberoftimesadsperday,rightorsomethingelse?
Commented by mr W last updated on 22/Nov/22
i divide one day (24h) into 48 equal  sections with length 30 min for each.  the ads come every 3 hours, that means  8 times every day. that means: in 8  of the 48 sections there are ads.   when we watch TV for 30 min in a   day,  we take one from the 48   sections, so the probability that it has   ads is (8/(48))=(1/6).
idivideoneday(24h)into48equalsectionswithlength30minforeach.theadscomeevery3hours,thatmeans8timeseveryday.thatmeans:in8ofthe48sectionsthereareads.whenwewatchTVfor30mininaday,wetakeonefromthe48sections,sotheprobabilitythatithasadsis848=16.
Commented by Acem last updated on 22/Nov/22
That′s good, thank you for sharing
Thatsgood,thankyouforsharing

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