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If-1-1-3-1-3-5-1-5-7-1-7-9-1-2017-2019-x-y-where-x-y-is-in-its-lower-terms-find-the-value-of-x-y-




Question Number 126963 by ZiYangLee last updated on 25/Dec/20
If (1/(1×3))+(1/(3×5))+(1/(5×7))+(1/(7×9))+…+(1/(2017×2019))=(x/y)  where (x/y) is in its lower terms,   find the value of x+y.
If11×3+13×5+15×7+17×9++12017×2019=xywherexyisinitslowerterms,findthevalueofx+y.
Answered by Olaf last updated on 25/Dec/20
S = Σ_(n=0) ^(1008) (1/((2n+1)(2n+3)))  S = (1/2)Σ_(n=0) ^(1008) [(1/(2n+1))−(1/(2n+3))]  S = (1/2)[1−(1/(2019))]  S = (1/2)×((2018)/(2019)) = ((1009)/(2019))  x = 1009, y = 2019, x+y = 3028
S=1008n=01(2n+1)(2n+3)S=121008n=0[12n+112n+3]S=12[112019]S=12×20182019=10092019x=1009,y=2019,x+y=3028
Commented by ZiYangLee last updated on 30/Dec/20
perfect!
perfect!

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