Menu Close

If-10-6-2-5-3-2-2-a-b-then-a-b-

Tinku Tara 0 Comments
Pin




Question Number 173869 by mnjuly1970 last updated on 20/Jul/22
If, ( (((√(10)) +(√6)+2)/( (√5) −(√(3 )) + (√2))) )^( 2) = a + (√b) then. a , b = ?
If,(10+6+25−3+2)2=a+bthen.a,b=?
Commented by infinityaction last updated on 20/Jul/22
(((√2)((√5)+(√3)+(√2)))/( (√5)−(√3)+(√2))) = A (((√2)((√5)+(√3))(1+((√2)/( (√5)+(√3)))))/( (√5)−(√3)+(√2))) = A (((√5)+(√3)((√2)+((2((√5)−(√3)))/( ((√5)+(√3))((√5)−(√3))))))/( (√5)−(√3)+(√2))) = A (((√5)+(√3)((√2)+((2((√5)−(√3)))/2)))/( (√5)+(√2)−(√3))) = A (√5)+(√3) = A A^2 = ((√5)+(√3))^2 = a+(√b) a+(√b) = 8+(√(60)) a = 8 , b =60
2(5+3+2)5−3+2=A2(5+3)(1+25+3)5−3+2=A5+3(2+2(5−3)(5+3)(5−3))5−3+2=A5+3(2+2(5−3)2)5+2−3=A5+3=AA2=(5+3)2=a+ba+b=8+60a=8,b=60
Commented by mnjuly1970 last updated on 20/Jul/22
thx alot sir
thxalotsir
Answered by Rasheed.Sindhi last updated on 20/Jul/22
If ( (((√(10)) +(√6)+2)/( (√5) −(√(3 )) + (√2))) )^( 2) = a + (√b) ( (((√(10)) +(√6)+2)/( (√5) −(√(3 )) + (√2))) )^( 2) =((10+6+4+4(√(15)) +4(√6) +4(√(10)))/(5+3+2−2(√(15)) −2(√6) +2(√(10)))) =((20+4(√(15)) +4(√6) +4(√(10)))/(10−2(√(15)) −2(√6) +2(√(10)))) =((10+2(√(15)) +2(√6) +2(√(10)))/(5−(√(15)) −(√6) +(√(10))))=(p/q) (say) ((10+2(√(15)) +2(√6) +2(√(10)))/(10−2(√(15)) −2(√6) +2(√(10))))=(p/(2q)) (((10+2(√(15)) +2(√6) +2(√(10)))+(10−2(√(15)) −2(√6) +2(√(10))))/((10+2(√(15)) +2(√6) +2(√(10)))−(10−2(√(15)) −2(√6) +2(√(10)))))=((p+2q)/(p−2q)) ((20+4(√(10)))/(4(√(15)) +4(√6)))=((p+2q)/(p−2q)) ((5+(√(10)))/( (√(15)) +(√6)))∙(((√(15)) −(√6))/( (√(15)) −(√6)))=((p+2q)/(p−2q)) ((5(√(15)) −5(√6) +5(√6) −2(√(15)) )/(15−6))=((p+2q)/(p−2q)) ((3(√(15)) )/9)=((p+2q)/(p−2q)) (((√(15)) )/3)=((p+2q)/(p−2q)) (((√(15)) +3 )/( (√(15)) −3))=(((p+2q)+(p−2q)/((p+2q)−(p−2q))) (((√(15)) +3 )/( (√(15)) −3))=((2p)/(4q))=(p/(2q)) (((√(15)) +3 )/( (√(15)) −3))∙(( (√(15)) +3)/( (√(15)) +3))=(p/(2q)) ((((√(15)) +3)^2 )/( 15 −9))=(p/(2q)) ((15+9+6(√(15)))/6)=(p/(2q)) ((24+6(√(15)))/3)=(p/q) =8+2(√(15)) =8+(√(60)) a=8 , b=60
If(10+6+25−3+2)2=a+b(10+6+25−3+2)2=10+6+4+415+46+4105+3+2−215−26+210=20+415+46+41010−215−26+210=10+215+26+2105−15−6+10=pq(say)10+215+26+21010−215−26+210=p2q(10+215+26+210)+(10−215−26+210)(10+215+26+210)−(10−215−26+210)=p+2qp−2q20+410415+46=p+2qp−2q5+1015+6⋅15−615−6=p+2qp−2q515−56+56−21515−6=p+2qp−2q3159=p+2qp−2q153=p+2qp−2q15+315−3=(p+2q)+(p−2q(p+2q)−(p−2q)15+315−3=2p4q=p2q15+315−3⋅15+315+3=p2q(15+3)215−9=p2q15+9+6156=p2q24+6153=pq=8+215=8+60a=8,b=60
Answered by Rasheed.Sindhi last updated on 20/Jul/22
If ( (((√(10)) +(√6)+2)/( (√5) −(√(3 )) + (√2))) )^( 2) = a + (√b) then. a , b = ? (((√(10)) +(√6)+2)/( (√5) −(√(3 )) + (√2)))=(((√2) ((√5) +(√3)+(√2) ))/( (√5) −(√(3 )) + (√2))) =^ (((√2) ((√5) +(√2)+(√3) ))/( (√5) +(√2)−(√(3 )) ))∙((((√5) +(√2)+(√3) ))/(((√5) +(√2)+(√3) ))) =(((√2) ((√5) +(√2)+(√3) )^2 )/(((√5) +(√2) )^2 −((√3))^2 )) =(((√2) (5+2+3+2(√(10)) +2(√6) +2(√(15)) ))/(5+2+2(√(10)) −3)) =(((√2) (10+2(√(10)) +2(√6) +2(√(15)) ))/(4+2(√(10)) )) =(((√2) (5+(√(10)) +(√6) +(√(15)) ))/(2+(√(10)) ))∙((2−(√(10)))/(2−(√(10)))) =(((√2) (10+2(√(10)) +2(√6) +2(√(15)) −5(√(10)) −10−(√(60)) −(√(150)) ))/(4−10)) =(((√2) (10 −3(√(10)) −10−3(√6) ))/(−6)) =(((√2) ((√(10)) +(√6) ))/2)=(( (√(10)) +(√6) )/( (√2) ))=(√5) +(√3) ▶( (((√(10)) +(√6)+2)/( (√5) −(√(3 )) + (√2))) )^( 2) =((√5) +(√3))^2 =5+3+2(√(15)) =8+2(√(15)) =8+(√(60)) a=8 ,b=60
If(10+6+25−3+2)2=a+bthen.a,b=?10+6+25−3+2=2(5+3+2)5−3+2=2(5+2+3)5+2−3⋅(5+2+3)(5+2+3)=2(5+2+3)2(5+2)2−(3)2=2(5+2+3+210+26+215)5+2+210−3=2(10+210+26+215)4+210=2(5+10+6+15)2+10⋅2−102−10=2(10+210+26+215−510−10−60−150)4−10=2(10−310−10−36)−6=2(10+6)2=10+62=5+3▸(10+6+25−3+2)2=(5+3)2=5+3+215=8+215=8+60a=8,b=60
Commented by mnjuly1970 last updated on 20/Jul/22
very nice sir thank you so much
verynicesirthankyousomuch

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *