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if-2x-3y-2020-find-maximum-value-3x-2y-for-x-and-natural-number-




Question Number 84188 by jagoll last updated on 10/Mar/20
if 2x+3y = 2020?  find maximum value 3x+2y for x and natural  number
if2x+3y=2020?findmaximumvalue3x+2yforxandnaturalnumber
Commented by jagoll last updated on 10/Mar/20
this diopthantine equation ?
thisdiopthantineequation?
Commented by jagoll last updated on 10/Mar/20
yes. my answer is correct. but my way  is different with you way sir
yes.myansweriscorrect.butmywayisdifferentwithyouwaysir
Commented by mr W last updated on 10/Mar/20
x=−3k+1007≥1  y=2k+2≥1  ⇒0≤k≤335    3x+2y=3(−3k+1007)+2(2k+2)  =3025−5k ≤3025  =3025−5k ≥1350    i.e. maximum of 3x+2y is 3025.  i.e. minimum of 3x+2y is 1350.
x=3k+10071y=2k+210k3353x+2y=3(3k+1007)+2(2k+2)=30255k3025=30255k1350i.e.maximumof3x+2yis3025.i.e.minimumof3x+2yis1350.
Commented by mr W last updated on 11/Mar/20
yes. there are many ways to solve.  i not only wanted to know the   minimum and maximum, but also  wanted to know the general solution  of the equation and how many solutions  it has. therefore i selected this way.
yes.therearemanywaystosolve.inotonlywantedtoknowtheminimumandmaximum,butalsowantedtoknowthegeneralsolutionoftheequationandhowmanysolutionsithas.thereforeiselectedthisway.

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