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if-3-2-1-2-i-find-z-11-




Question Number 146467 by mathdanisur last updated on 13/Jul/21
if    ((√3)/2) + (1/2) i    find   z^(11)  = ?
if32+12ifindz11=?
Answered by gsk2684 last updated on 13/Jul/21
z^(11)  = (cis (Π/6))^(11) = cis(((11Π)/6))  =cis(2Π−(Π/6))  =cis(−(Π/6))  =((√3)/2)−(i/2)
z11=(cisΠ6)11=cis(11Π6)=cis(2ΠΠ6)=cis(Π6)=32i2
Commented by mathdanisur last updated on 13/Jul/21
thanks Ser, but cis.? cos.?
thanksSer,butcis.?cos.?
Commented by gsk2684 last updated on 13/Jul/21
cis θ = cos θ + i sin θ
cisθ=cosθ+isinθ
Commented by mathdanisur last updated on 13/Jul/21
thanks Ser
thanksSer
Answered by puissant last updated on 13/Jul/21
Z=cos(π/6)+i sin(π/6)=e^(i(π/6))   Z^(11) =(e^(i(π/6)) )^(11) =e^(i((11π)/6)) = cos((11π)/6)+i sin((11π)/6)  ⇒ Z=((√3)/2)−(1/2)i
Z=cosπ6+isinπ6=eiπ6Z11=(eiπ6)11=ei11π6=cos11π6+isin11π6Z=3212i
Commented by mathdanisur last updated on 13/Jul/21
thank you Ser  cos((11π)/6)+isin((11π)/6)⇒z^(11) =((√3)/2)−(1/2)i.?
thankyouSercos11π6+isin11π6z11=3212i.?
Commented by mathdanisur last updated on 13/Jul/21
thanks Ser
thanksSer

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