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If-3-2019-k-is-a-multiple-of-11-find-the-smallest-positive-integer-k-




Question Number 124931 by ZiYangLee last updated on 07/Dec/20
If 3^(2019) +k is a multiple of 11,   find the smallest positive integer k.
If32019+kisamultipleof11,findthesmallestpositiveintegerk.
Answered by MJS_new last updated on 07/Dec/20
3^0 =11n+1  3^1 =11n+3  3^2 =11n+9  3^3 =11n+5  3^4 =11n+4  3^5 =11n+1  3^6 =11n+3  ...  ⇒  3^(5m) =11n+1  3^(5n+1) =11n+3  3^(5m+2) =12n+9  3^(5m+3) =11n+5  3^(5m+4) =11n+4  2019=5m+4 ⇒ 3^(2019) =11n+4 ⇒ k=7
30=11n+131=11n+332=11n+933=11n+534=11n+435=11n+136=11n+335m=11n+135n+1=11n+335m+2=12n+935m+3=11n+535m+4=11n+42019=5m+432019=11n+4k=7

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