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If-4sinx-cosy-2sinx-2cosy-1-0-where-x-y-0-2pie-Find-largest-possible-value-of-the-sum-x-y-




Question Number 29491 by math solver last updated on 09/Feb/18
If 4sinx.cosy+2sinx+2cosy+1=0  where x,y ∈ [0,2pie]. Find largest   possible value of the sum (x+y).
If4sinx.cosy+2sinx+2cosy+1=0wherex,y[0,2pie].Findlargestpossiblevalueofthesum(x+y).
Answered by ajfour last updated on 09/Feb/18
(1+2sin x)(1+2cos y)=0  ⇒  sin x=−(1/2) ;  cos y = whatever  or  cos y=−(1/2);  sin x= whatever  in this case  (x+y)_(max)  =2π+(π+(π/3)) =((10π)/3)  under first case  (x+y)_(max)  = (2π−(π/6))+2π = ((23π)/6)  Hence  (x+y)_(max)  =((23π)/6) .
(1+2sinx)(1+2cosy)=0sinx=12;cosy=whateverorcosy=12;sinx=whateverinthiscase(x+y)max=2π+(π+π3)=10π3underfirstcase(x+y)max=(2ππ6)+2π=23π6Hence(x+y)max=23π6.
Commented by math solver last updated on 09/Feb/18
thank you sir.
thankyousir.

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