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If-5-2-3-5-7-3-3-2-5-7-9-4-3-3-then-find-the-value-of-2-4-




Question Number 22547 by Tinkutara last updated on 20/Oct/17
If α = (5/(2!3)) + ((5.7)/(3!3^2 )) + ((5.7.9)/(4!3^3 )) ,... then find  the value of α^2  + 4α.
Ifα=52!3+5.73!32+5.7.94!33,thenfindthevalueofα2+4α.
Answered by ajfour last updated on 20/Oct/17
(1+x)^n =1+nx+((n(n−1))/(2!))x^2 +...  let x=−(2/3)  ,n→−n  (1+x)^(−n) ∣_(x=−(2/3)) =1+((2n)/3)+((2n(2n+2))/(2!3^2 ))                       +((2n(2n+2)(2n+4))/(3!3^3 ))+..  let n=3/2  ⇒(1−(2/3))^(−3/2) =1+1+(5/(2!3))+((5.7)/(3!3^2 ))+..  ⇒ 3(√3) =2+α    α=3(√3)−2    α^2 +4α=α(α+4)        =(3(√3)−2)(3(√3)+2)        =23 .
(1+x)n=1+nx+n(n1)2!x2+letx=23,nn(1+x)nx=23=1+2n3+2n(2n+2)2!32+2n(2n+2)(2n+4)3!33+..let\boldsymboln=3/2(123)3/2=1+1+52!3+5.73!32+..33=2+αα=332α2+4α=α(α+4)=(332)(33+2)=23.
Commented by ajfour last updated on 20/Oct/17
seeking 𝛂 .
seeking\boldsymbolα.
Commented by Tinkutara last updated on 20/Oct/17
How you have written x=−(2/3), n=(3/2)?
Howyouhavewrittenx=23,n=32?
Commented by Tinkutara last updated on 03/Jan/18
Thanks Sir!
Commented by ajfour last updated on 03/Jan/18
α need to be generated, 3, 3^2 , 3^3 ,..  in denominator coaxed me to  put x=(2/3) , ...
αneedtobegenerated,3,32,33,..indenominatorcoaxedmetoputx=23,

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