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If-a-3-a-1-0-then-find-the-valueof-a-4-a-3-a-2-2a-1-




Question Number 49123 by Pk1167156@gmail.com last updated on 03/Dec/18
If  a^3 −a−1=0  then find the valueof  a^4 +a^3 −a^2 −2a+1
Ifa3a1=0thenfindthevalueofa4+a3a22a+1
Commented by behi83417@gmail.com last updated on 03/Dec/18
a^3 =a+1  =a^3 (a+1)−(a+1)^2 +2=a^3 (a^3 )−(a^3 )^2 +2=2 .
a3=a+1=a3(a+1)(a+1)2+2=a3(a3)(a3)2+2=2.
Answered by mr W last updated on 03/Dec/18
a^3 =a+1  a^4 +a^3 −a^2 −2a+1  =a(a+1)+a^3 −a^2 −2a+1  =a^3 −a+1  =a^3 −a−1+2  =0+2  =2
a3=a+1a4+a3a22a+1=a(a+1)+a3a22a+1=a3a+1=a3a1+2=0+2=2

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