Question Number 92425 by Jidda28 last updated on 06/May/20
$$\mathrm{If}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{are}\:\mathrm{two} \\ $$$$\mathrm{different}\:\mathrm{number}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{A}+\mathrm{B}=\mathrm{C}\:\mathrm{and}\:\mathrm{A}×\mathrm{B}=\mathrm{C} \\ $$$$\mathrm{find}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}. \\ $$
Commented by mr W last updated on 06/May/20
$${A}\neq{B} \\ $$$${A}+{B}={A}×{B} \\ $$$${there}\:{are}\:{infinite}\:{such}\:{numbers}: \\ $$$${for}\:{each}\:{A}\neq\mathrm{0},\neq,\neq\mathrm{2}\:{there}\:{is}\:{a}\:{B}: \\ $$$${B}=\frac{{A}}{{A}−\mathrm{1}} \\ $$