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if-a-b-c-0-find-the-value-of-a-2-bc-b-2-ca-c-2-ab-

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Question Number 171826 by Mikenice last updated on 21/Jun/22
if a+b+c=0,find the value of (a^2 /(bc))+(b^2 /(ca))+(c^2 /(ab))
ifa+b+c=0,findthevalueofa2bc+b2ca+c2ab
Answered by nimnim last updated on 21/Jun/22
(a^2 /(bc))+(b^2 /(ca))+(c^2 /(ab)) =((a^3 +b^3 +c^3 )/(abc)) =((a^3 +b^3 +c^3 )/(abc))−3+3 =((a^3 +b^3 +c^3 −3abc)/(abc))+3 =(((a+b+c)(a^2 +b^2 +c^2 −ab−bc−ca))/(abc))+3 =(((0)(a^2 +b^2 +c^2 −ab−bc−ca))/(abc))+3 =0+3 =3
a2bc+b2ca+c2ab=a3+b3+c3abc=a3+b3+c3abc−3+3=a3+b3+c3−3abcabc+3=(a+b+c)(a2+b2+c2−ab−bc−ca)abc+3=(0)(a2+b2+c2−ab−bc−ca)abc+3=0+3=3
Commented by Mikenice last updated on 21/Jun/22
thanks sir
thankssir

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